홀짝에 따라 다른 값 반환하기

// javascript
const solution = (n) => {
    return n % 2 === 1 
        ? Array.from({ length: Math.floor(n / 2) + 1 }, (_, index) => index * 2 + 1).reduce((sum, num) => sum + num, 0) 
        : Array.from({ length: n / 2 }, (_, index) => (index + 1) * 2).reduce((sum, num) => sum + num * num, 0);
}

// typescript
const solution = (n: number): number => {
    return n % 2 === 1 
        ? Array.from({ length: Math.floor(n / 2) + 1 }, (_, index) => index * 2 + 1).reduce((sum, num) => sum + num, 0) 
        : Array.from({ length: n / 2 }, (_, index) => (index + 1) * 2).reduce((sum, num) => sum + num * num, 0);
}